Question

x²-13x+12=0 como resolvo ?

Answer 1

Δ= b²+2ac
Δ= (13)² + 2 × 1× 12
Δ= 169 + 24
Δ= 193

Answer 2

x²-13+12=0

a=1       b=-13        c=12

Δ=b²-4ac

Δ=(-13)²-4.(1).(+12)

Δ=169-48

Δ=121

x=√Δ

x=√121

x=11

x'= -b+√Δ/2a

x'=(-(-13)+11)/2

x'=(+13+11)/2

x'=24/2

x'=12

x"= -b-√Δ/2a

x"=(-(-13)-11)/2

x"= (+13-11)/2

x"= 2/2

x"= 1                          S=(1 , 12)