Question

x²-13+12=0 use a bhaskara

Answer 1

x² - 4 .a.c
Δ = b² - 4.a.c
Δ = (-13)² -  4 .1 . 12
Δ = 169  - 48
Δ = 121 ⇒√121 = 11
x = - b + ou - 11/2
x´= -(-13) + 11/2
x´ = 13 + 11/2
x´= 24/2 ⇒ 12
x´´ = 13 - 11/2
x´´ = 2/2 ⇒ 1
S = {1,12}