Question

x2 + 12x – 13 = 0 pela forma de bhaskara​

Answer 1

x² +12x -13=0 => a=1, b=12, c=-13
∆=b²-4.a.c =(-12)²-4.1.(-13)= 144+52=196
√∆ = 14

x= -b±√∆/2a

x= -12±14/2.1

x' = -12+14/2 = 2/2= 1 ✓

x" = -12-14/2 = -26/2 = -13 ✓

Answer 2

X² + 12x - 13=0

a= 1, b= 12, c= - 13

Delta= b ² - 4.a.c

Delta= 12² - 4. 1. (-13)

Delta= 144+ 52

Delta = 196

$x = \frac{ - b + - \sqrt{delta} }{2.a}$

$x = \frac{ - 12 + - \sqrt{196} }{2.1}$

$x = \frac{ - 12 + 14}{2} = \frac{2}{2} = 1$

$x = \frac{ - 12 - 14}{2} = \frac{ - 26}{2} = - 13$