Question

x2+12x-12=0 preciso fazer essa conta mais nao sei​

Answer 1

Achamos por Bhaskara.

∆= b²-4ac

∆= 12²-4*1*(-12)

∆= 144 + 48

∆= 192

x = -12 ±√192 / 2

Answer 2

Resposta:

x² +12x -12=0

coeficientes

a=1

b=12

c=-12

Δ=b²-4ac

Δ=12²-4(1)(-12)

Δ=144+48

Δ=192

$x={-b\pm\sqrt{\Delta} \over2a}={-12\pm\sqrt{192} \over2(1)}={-12\pm\sqrt{2^6.3} \over2}=\\ \\ x={-12\pm2^3\sqrt{3} \over2}={-12\pm8\sqrt{3} \over2}={\not2(-6\pm4\sqrt{3}) \over\not2}={-6\pm\sqrt{3} )$

$x_1=-6-4\sqrt{3} \\ \\ x_2=-6+4\sqrt{3}$