Question

x²+12x 11=0 respondam ae com o calcaulo do delta.

Answer 1

Boa noite!
X²+12X+11=0
a = 1, b = 12, c = 11
Δ = b² - 4ac
Δ = 12² - 4. 1. 11
Δ = 144  - 44
Δ = 100
X = - b+-√Δ/2a
X = -12+-√100/2.1
X = -12 +- 10/ 2
X' = -12 - 10 /2 = -22/2 = -11
X" = -12 + 10/2 = -2/2 = -1
S = {(-11, -1)}

Espero ter ajudado  ;)

Answer 2

x² + 12x + 11 = 0

a = 1
b = 12
c = + 11

Δ = b² - 4.a.c
Δ = 12² - 4.1. (+ 11)
Δ = 144 - 44
Δ = 100

x = - b + - √Δ/2a
x = - 12 + - √100/2.1
x = - 12 + - 10/2

x' = - 12 - 10/2 ⇒ x' = - 22/2 ⇒ x' = - 11
x" = - 12 + 10/2 ⇒ x" = - 2/2 ⇒ x" = - 1

S = {  -11 e - 1 }