Question

x²-10x+24=0

resposta?​

Answer 1

∆=100-96=4

x = 10±√4/2

x = 10±2/2

x' = 10+2/2 = 6

x" = 10-2/2 = 4

Answer 2

Resposta:

$S=\{4,~6\}$

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-10x+24=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-10~e~c=24\\\\\Delta=(b)^{2}-4(a)(c)=(-10)^{2}-4(1)(24)=100-(96)=4\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-10)-\sqrt{4}}{2(1)}=\frac{10-2}{2}=\frac{8}{2}=4\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-10)+\sqrt{4}}{2(1)}=\frac{10+2}{2}=\frac{12}{2}=6\\\\S=\{4,~6\}$