Question

x² + 10x + 20 = -4 ???????​

Answer 1

Resposta:

x$^{2}$+10x+20+4=0       x$^{2}$+10x+24=0

Δ=b$^{2}$-4.a.c    Δ= 10$^{2}$-4.1.24 = 100-96 = 4  Δ=4

x= $\frac{-10±\sqrt{4} }{2.1}$=$\frac{-10±2}{2}$

x`=$\frac{-10-2}{2}$=-6

x``=$\frac{-10+2}{2}$=-4

Explicação passo-a-passo: