Question

-x²+10x-16=0 fórmula de bhaskara​

Answer 1

-x²+10x-16=0

Δ = (10)² - 4.- 1. -16

Δ = 100 - 64

Δ = 36

x = -10 (+ -) √36/ 2. -1

x' = -10 + 6 / -2 = -4/ -2 = 2

x'' = -10 - 6/ -2 =  -16/ -2 = 8

S = {2, 8}

Answer 2

Resposta:

2 ou 8

Explicação passo-a-passo:

delta = b^2-4ac

-10^2-4*1*16

100-64 = 36

√36 = 6

formula de Bhaskara = -b +-√Δ / 2a

-(-10)+-√36 / 2*1

10+-6/2*1

10-6/2*1 = 4/2

4/2 = 2

ou

10+6/2*1 = 16/2

16/2 = 8