Question

(x2-1) (x2-12)+24=0

Answer 1

(2x-1)(2x-12)+24=0

$4x^2 - 24x -2x +12 +24 = 0$

$4x^2- 26 x + 36 = 0$

$2x^2 - 13x + 18 = 0$

realiza a fórmula de Bhaskara

$Δ = b^2 - 4*a*c$

$Δ = 13^2 -4*2*18$

Δ = 169 -144

Δ = 25

(-b $^{+/- 2}\sqrt{Δ}$ )/ 2*


$x^I =\frac{ -(-13) + \sqrt{25} }{2*2} = \frac{13+5}{4} = \frac {18}{4} = \frac{9}{2}$ 

$x^{II} =\frac{ -(-13) - \sqrt{25} }{2*2} = \frac{13-5}{4} = \frac {8}{4} = 2$