Question

x+y=3
2x+3y=8 me ajudem pur favor​

Answer 1

OLÁ VAMOS A SUA PERGUNTA:⇒⇒

$\left. \begin{cases} { x+γ=3 } \\ { 2x+3γ=8 } \end{cases} \right.$

$x+\gamma =3,2x+3\gamma =8$

$\left(\begin{matrix}1&1\\2&3\end{matrix}\right)\left(\begin{matrix}x\\\gamma \end{matrix}\right)=\left(\begin{matrix}3\\8\end{matrix}\right)$

$inverse(\left(\begin{matrix}1&1\\2&3\end{matrix}\right))\left(\begin{matrix}1&1\\2&3\end{matrix}\right)\left(\begin{matrix}x\\\gamma \end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\2&3\end{matrix}\right))\left(\begin{matrix}3\\8\end{matrix}\right)$

$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\\gamma \end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\2&3\end{matrix}\right))\left(\begin{matrix}3\\8\end{matrix}\right)$

$\left(\begin{matrix}x\\\gamma \end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\2&3\end{matrix}\right))\left(\begin{matrix}3\\8\end{matrix}\right)$

$\left(\begin{matrix}x\\\gamma \end{matrix}\right)=\left(\begin{matrix}\frac{3}{3-2}&-\frac{1}{3-2}\\-\frac{2}{3-2}&\frac{1}{3-2}\end{matrix}\right)\left(\begin{matrix}3\\8\end{matrix}\right)$

$\left(\begin{matrix}x\\\gamma \end{matrix}\right)=\left(\begin{matrix}3&-1\\-2&1\end{matrix}\right)\left(\begin{matrix}3\\8\end{matrix}\right)$

$\left(\begin{matrix}x\\\gamma \end{matrix}\right)=\left(\begin{matrix}3\times 3-8\\-2\times 3+8\end{matrix}\right)$

$\left(\begin{matrix}x\\\gamma \end{matrix}\right)=\left(\begin{matrix}1\\2\end{matrix}\right)$

$\star \: \text{Extraia os elementos x e y da matriz.}$

$\color{blue}{}\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese  x=1,y =2 }}}\ \checkmark$

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