Matemática, perguntado por mariaeunicerochae, 7 meses atrás

{x-y=2
{4x+y=32

{x+y=18
{4x-y=12

Soluções para a tarefa

Respondido por RoRoHoul
1

Primeiro sistema:

\displaystyle\left\{    \begin{array}{l}        x-y=2\\        4x+y=32    \end{array}\right.\\\\x+4x-y+y=2+32\\5x=34\\\\x=\frac{34}{5}\\\\\\x-y=2\\\frac{34}{5}-y=2\\\\-y=2-\frac{34}{5}\\\\-y=-\frac{24}{5}\\\\y=\frac{24}{5}\\

Segundo sistema:

\displaystyle\left\{    \begin{array}{l}        x+y=18\\        4x-y=12    \end{array}\right\\\\x+4x+y-y=18+12\\5x=30\\x=6\\\\x+y=18\\6+y=18\\y=18-6\\y=12

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