Question

x-y=1
x²+y²=13
???????????

Answer 1

X-y=1
$x=y+1 (y+1)^2+y^2=13 y^2+1^2+y^2=13 2y^2=13-1 2y^2=12 y^2= \frac{12}{2} y^2 = 6 y= \sqrt{6}$ x²+y²=13

$x=y+1 \\x= \sqrt{6} + 1$