{x;(x²+1/x);(x²+2/x)}
Soluções para a tarefa
Respondido por
0
[x1]=[−3√2]
[x2]=[3√(−1)3√2]
\left[x _{3}\right] = \left[ - \left( -1\right) ^{\frac{2}{3}}\,\sqrt[3]{2}\right][x3]=[−(−1)323√2]
[x2]=[3√(−1)3√2]
\left[x _{3}\right] = \left[ - \left( -1\right) ^{\frac{2}{3}}\,\sqrt[3]{2}\right][x3]=[−(−1)323√2]
Perguntas interessantes