Matemática, perguntado por luizamorena57, 5 meses atrás

x(x+6)=2x(x-3)
preciso urgente ​

Soluções para a tarefa

Respondido por FalhaNoSO
1

x(x+6) = 2x(x-3)

x.x + x.6 = 2x.x -2.x.3

x² + 6x = 2x² -6x

x²-2x²+6x+6x = 0

-x² + 12x = 0

x² - 12x = 0

x.(x - 12) = 0

x' = 0

x - 12 = 0

x'' = 12

Respondido por Rafaelcdepaula
1

\mathsf{x(x+6)=2x(x-3)}\\\\\mathsf{x^2+6x=2x^2-6x}\\\\\mathsf{x^2-2x^2+6x+6x=0}\\\\\mathsf{-x^2+12x=0}

\mathsf{\Delta=b^2-4ac}\\\mathsf{\Delta=12^2-4\cdot(-1)\cdot0}\\\mathsf{\Delta=144}

\mathsf{x=\dfrac{-b\pm\sqrt\Delta}{2a}}\\\\\mathsf{x=\dfrac{-12\pm\sqrt{144}}{2\cdot(-1)}}\\\\\mathsf{x=\dfrac{-12\pm12}{-2}}

\mathsf{x_1=\dfrac{-12+12}{-2}=\dfrac0{-2}=0}\\\\\mathsf{x_2=\dfrac{-12-12}{-2}=\dfrac{-24}{-2}=\dfrac{24}{2}=12}

\boxed{\boxed{\mathsf{S=\{0, 12\}}}}


luizamorena57: tenho outras perguntas,se quiser responder está no meu perfil
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