Question

x (x+2) = 2 x + 25


pooor favor me ajudem


x(x+1)=0


2x (x-5)=0

(x + 3 ). (x-1) =0

(x-6).(4 x -8)=0

Answer 1

x(x+2) = 2x + 25
x² + 2x = 2x+ 25
x² = 25
x= + ou - 5

2x(x-5) = 0
2x² - 10x = 0  :2
x² -5x = 0
S= 5           x1= 5
P= 0           x2=0

(x+3)(x-1) = 0
x² -x + 3x -3 = 0
x² + 2x - 3=0
S= -2        x1=3
P= -3        x2=-1

(x-6)(4x-8) = 0
4x² - 8x - 24x + 48 = 0
4x² - 32x +48 = 0    :4
x² - 8x +12 = 0 
S=8        x1=6
P=12      x2=2

Espero ter te ajudado

Answer 2

x (x+2)=2x+25
x^2+2x=2x+25
x^2+2x-2x=25
x^2=25
x= raiz de 25
x=-/+ 5

x(x+1)=0
x=0
x+1=0
x=0-1
x=-1

2x(x-5)=0
2x^2-10x=0
delta=b^2-4ac
delta=(-10)^2-4.2.0
delta=100-0
delta=100
x=-b-/+ raiz de delta/2a
x=-(-10)-10/2.2
x=10-10/4
x=0/4
x=0
x=-(-10)+10/2.2
x=10+10/4
x=20/4
x=5

(x+3).(x-1)=0
x^2-x+3x-3
x^2+2x-3=0
delta=b^2-4ac
delta=2^2-4.1.(-3)
delta=4+12
delta=16
x=-b-/+ raiz de delta/2a
x=-2-4/2.1
x=-6/2
x=-3
x=-2+4/2.1
x=2/2
x=1

(x-6). (4x-8)=0
4x^2-8x-24x+48
4x^2-32x+48=0
delta=b^2-4ac
delta=(-32)^2-4.4.48
delta=1024-768
delta=256
x=-b-/+ raiz de delta/2a
x=-(-32)-16/2.4
x=32-16/8
x=16/8
x=2
x=-(-32)+16/2.4
x=32+16/8
x=48/8
x=6