Question

x
${x}^{2} + 6x - 16 = 0$


me ajudem por favor tenho que entregar amanhã 7:30

Answer 1

${x}^{2} + 6x - 16 = 0$
Δ=$b^{2} - 4*a*c \\ 6^{2} - 4*1*(-16) \\ 36 +64 \\ 100$
$x= \frac{-6+ou- \sqrt{100} }{2} \\ x= \frac{-6+ou- 10}{2} \\ \\ x_{1} = \frac{-6+10}{2} \\x_{1} = \frac{4}{2} \\ x_{1} =2 \\ \\ x_{2} = \frac{-6-10}{2} \\ x_{2} = \frac{-16}{2} \\ x_{2} = -8$