Question

X expoente 2 =x+12 me ajudem pra escola

Answer 1

Explicação passo-a-passo:

$x^2=x+12$

$x^2-x-12=0$

$\Delta=(-1)^2-4\cdot1\cdot(-12)$

$\Delta=1+48$

$\Delta=49$

$x=\dfrac{-(-1)\pm\sqrt{49}}{2\cdot1}=\dfrac{1\pm7}{2}$

$x'=\dfrac{1+7}{2}~\longrightarrow~x'=\dfrac{8}{2}~\longrightarrow~x'=4$

$x"=\dfrac{1-7}{2}~\longrightarrow~x"=\dfrac{-6}{2}~\longrightarrow~x"=-3$

$S=\{-3,4\}$

Answer 2

Oie, Td Bom?!

$x {}^{2} = x + 12 \\ x {}^{2} - x - 12 = 0 \\ x {}^{2} + 3x - 4x - 12 = 0 \\ x \: . \: (x + 3) - 4(x + 3) = 0 \\ (x + 3) \: . \: (x - 4) = 0$

$x + 3 = 0⟶x = - 3 \\ x - 4 = 0⟶x = 4$

S = $\left \{ x_{1} = - 3 \: , \: x_{2} = 4 \right \}$

Att. Makaveli1996