Question

X elevado ao quadrado + 4x + 3 = 0

Answer 1

Podemos resolver pelo método de Bhaskara:

$x^2+4x+3=0$.

coeficientes:
$a=1$;
$b=4$;
$c=3$.

Δ$=b^2-4ac$ =>
Δ$=4^2-4.1.3$ =>
Δ$=16-12$ =>
Δ$=4$.

$x=\frac{-b\frac{+}{-}\sqrt{DELTA}}{2a}$ =>
$x=\frac{-4\frac{+}{-}\sqrt{4}}{2}$.

$x_{1}=\frac{-4+2}{2}$ =>
$x_{1}=\frac{-2}{2}$ =>
$x_{1}=-1$.

$x_{2}=\frac{-4-2}{2}$ =>
$x_{2}=\frac{-6}{2}$ =>
$x_{2}=-3$.

S = { -3, -1 }.