Question

x elevado a 2 menos 6x mais 9 igual a zero
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Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-6x+9=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-6~e~c=9\\\\\Delta=(b)^{2}-4(a)(c)=(-6)^{2}-4(1)(9)=36-(36)=0\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-6)-\sqrt{0}}{2(1)}=\frac{6-0}{2}=\frac{6}{2}=3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-6)+\sqrt{0}}{2(1)}=\frac{6+0}{2}=\frac{6}{2}=3\\\\S=\{3,~3\}$

Answer 2

resolução!

${x}^{2} - 6x + 9 = 0$

∆ = (-6)^2 - 4 * 1 * 9

∆ = 36 - 36

∆ = 0

X = 6 + 0/2

X = 6/2

X = 3

S = { 3 }