Question

x Elevado a 2-5x +6=​

Answer 1

Olá.

x² - 5x + 6 = 0

Separando os coeficientes:

a= 1 ; b = - 5 ; c = 6

Calculando discriminante

Δ = b² - 4 • a c

Δ = (-5)² - 4 • 1 • 6

Δ = 25 - 24

Δ = 1

Raízes:

x = - b ± √ Δ /2 • a

x = 5 ± √1 / 2 • 1

x = 5 ± 1 / 2

x1 = 5 + 1 / 2 = 6/2 = 3

x2 = 5 - 1 /2 = 4/2 = 2

S (3, 2 )

Answer 2

${x}^{2} - 5x + 6 = 0$
$a = 1 \: b = - 5 \: c = 6$
$delta = {b}^{2} - 4ac$
$delta = { - 5}^{2} - 4 \times 1 \times 6 \\ = 25 - 24$
$= 1$
$x1e2 = \frac{ - b - + \sqrt{delta} }{a \times 2}$
$x1e2 = \frac{ 5 + \sqrt{1} }{1 \times 2}$
$x1 = \frac{ 5 + 1}{2}$
$x1 = \frac{ 6}{2} = 3$
$x2 = \frac{ 5 - 1}{2} = 2$
solução:
$x1 = 3 \\ x2 = 2$