Question

x elevado a 2 -5x+6=0

Answer 1

$x^2-5x+6=0$

Coeficientes: a = 1, b = -5 e c = 6

$\Delta=b^2-4ac\\\Delta=(-5)^2-4\cdot1\cdot6\\\Delta=25-24\\\Delta=1$

$x=\dfrac{-b\pm\sqrt{\Delta}}{12a}\\\\x=\frac{-(-5)\pm\sqrt{1}}{2\cdot1}\\\\x=\frac{5\pm1}{2}\\\\x_1=\frac{5+1}{2}=\frac{6}{2}=3\\\\x_2=\frac{5-1}{2}=\frac{4}{2}=2$



Espero ter ajudado.
Bons estudos! :)

Answer 2

Boa tarde

x² - 5x + 6 = 0

S = 2 + 3 = 5
P = 2*3 = 6 

x1 = 2
x2 = 3