Question

X elevado a 2 -4x mais 3 é igual a 0

Answer 1

$x^2 - 4x + 3 = 0 \\ \\ a = 1 \\ b = -4 \\ c = 3 \\ \\ x = \frac{-b\pm \sqrt{b^2-4.a.c} }{2.a} \\ \\ x = \frac{-(-4)\pm \sqrt{(-4)^2-4.1.3} }{2.1} \\ \\ x = \frac{4\pm \sqrt{16-12} }{2} \\ \\ x = \frac{4\pm \sqrt{4} }{2} \\ \\ x = \frac{4\pm2}{2} \\ \\ \\ x' = \frac{4+2}{2} \rightarrow x' = \frac{6}{2} \rightarrow x' = 3 \\ \\ x'' = \frac{4-2}{2} \rightarrow x'' = \frac{2}{2} \rightarrow x'' = 1$

Raízes:

$x' = 3 \\ x'' = 1$

Answer 2

$x^{2} -4x +3 =0$            
a=1/ b= -4/ c=3
Δ=$b^{2} - 4ac$
Δ=$-4^{2} -4*1*3$
Δ=16-12
Δ=4

x=  $\frac{-b+ou- \sqrt{delta} }{2*a}$
x=$\frac{-(-4)+ou - \sqrt{4} }{2*1}$
x=$\frac{4+ou-2}{2}$
x1=$\frac{4+2}{2}$ →6/2→3
x2=$\frac{4-2}{2}$→2/2→1