Question

X elevado 2+5x+6=0 /pfv me ajundem

Answer 1

Resposta:

$x^{2} +5x+6=0$

Fórmula de Bhaskara

coeficientes: a = 1, b = 5, c = 6

$delta=b^{2} -4.a.c\\ \\ delta=5^{2} -4.1.6\\ \\ delta=25-24\\ \\ delta=1$

$x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-5+-\sqrt{1} }{2.1} \\ \\ x=\frac{-5+-1}{2} \\ \\ x'=\frac{-5+1}{2} =-\frac{4}{2} =-2\\ \\ x''=\frac{-5-1}{2} =-\frac{6}{2} =-3\\ \\ \\ S~\left \{ {{-2,~-3} {}} \}$