Question

x ao quadrado+x=0 usando o delta

Answer 1

x²+x+0 = 0

DELTA: 1² - 4*(1)*(0) = 1

$x= \frac{-1\pm1}{2} \\ \\ x'= \frac{0}{2} =0 \\ \\ x"= \frac{-2}{2}=-1$

Answer 2

x² + x = 0
a = 1; b = 1; c = 0

Δ = b² - 4ac
Δ = 1² - 4.1.0
Δ = 1

x = - b +/- √Δ = - 1 +/- √1
           2a             2.1

x = - 1 + 1 =  0
         2

x = - 1 - 1 = -2/2 = - 1
          2

R. x = 0 e x = - 1

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Outra forma:

x² + x = 0
x(x + 1) = 0

x = 0

x + 1 = 0
x = - 1

R.: x = 0 e x = - 1