x ao quadrado menos raiz de 2 igual a 0
Soluções para a tarefa
Respondido por
0
Vamos lá :
![x^2 - \sqrt{2} = 0 \\ \\
x^2 = \sqrt{2} \\ \\
x = \pm ~\sqrt{ \sqrt{2} } \\ \\
x = \pm ~\sqrt[4]{2} ~~~~~~~~ou ~~~~~~~~x = \pm~ 2^{\frac{1}{4}} \\ \\
S =\{ - ~ 2^{\frac{1}{4}} , ~2^{\frac{1}{4}} \} x^2 - \sqrt{2} = 0 \\ \\
x^2 = \sqrt{2} \\ \\
x = \pm ~\sqrt{ \sqrt{2} } \\ \\
x = \pm ~\sqrt[4]{2} ~~~~~~~~ou ~~~~~~~~x = \pm~ 2^{\frac{1}{4}} \\ \\
S =\{ - ~ 2^{\frac{1}{4}} , ~2^{\frac{1}{4}} \}](https://tex.z-dn.net/?f=x%5E2+-+%5Csqrt%7B2%7D+%3D+0+%5C%5C++%5C%5C+%0Ax%5E2+%3D+%5Csqrt%7B2%7D+%5C%5C++%5C%5C+%0Ax+%3D+%5Cpm+%7E%5Csqrt%7B+%5Csqrt%7B2%7D+%7D++%5C%5C++%5C%5C+%0Ax+%3D+%5Cpm+%7E%5Csqrt%5B4%5D%7B2%7D+%7E%7E%7E%7E%7E%7E%7E%7Eou+%7E%7E%7E%7E%7E%7E%7E%7Ex+%3D+%5Cpm%7E+2%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D+%5C%5C++%5C%5C+%0A%0AS+%3D%5C%7B+-+%7E+2%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D+%2C+%7E2%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D+%5C%7D)
Espero ter ajudado !!!
Espero ter ajudado !!!
Perguntas interessantes