Question

X ao quadrado - 8x +12 =0 me ajude Pf

Answer 1

Bom Dia !!!

Resolvendo por bháskara.

x² - 8x + 12 = 0

a = 1

b = -8

c = 12

Δ = b² -4.a.c

Δ = 64 - 4.1.12

Δ = 64 - 48

Δ = 16

$\frac{-b-+\sqrt{16} }{2.a}$

$\frac{8-+4}{2}$

x1 = 4/2

x1 = 2

x2 = 12/2

x2 = 6

Espero ter ajudado :-)

Att: LDC

Answer 2

x²-8x+12=0

Δ= b²-4ac

Δ=-8²-4.1.12

Δ= 64-48 = 16

x=8+-4/2

x'=12/2 = 6

x''= 4/2=2