Question

X ao quadrado-5x+6=0

Answer 1

$\large\boxed{\begin{array}{l} \rm \: x {}^{2} - 5x + 6 = 0 \\ \\ \Rightarrow \begin{cases} \rm \: a = 1 \\ \rm \: b = - 5 \\ \rm \: c = 6\end{cases} \\ \\ \rm\Delta = b {}^{2} - 4ac \\ \Delta = ( - 5) {}^{2} - 4 \: . \: 1 \: . \: 6 \\ \Delta = 25 - 24 \\\Delta = 1 \\ \\ \rm \: x = \dfrac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ \rm \: x = \dfrac{ - ( - 5) \pm \sqrt{1} }{2.1} \\ \\ \rm \: x = \dfrac{5 \pm1}{2} \begin{cases} \rm \: x_1 = \dfrac{5 + 1}{2} = \dfrac{6}{2} = \boxed{3} \\ \\ \rm \: x_2 = \dfrac{5 - 1}{2} = \dfrac{4}{2} = \boxed{2} \end{cases}\end{array}}$

Answer 2

Resposta:

V = {2  3}

Explicação passo a passo:

x² - 5x + 6 = 0

(x -3)(x - 2) = 0

x - 3 = 0 ⇒ x' = 3

x - 2 = 0 ⇒ x'' = 2

V = {2  3}