Question

x AO QUADRADO -5X+6=0

Answer 1

podemos usar a formula de bhaskara sim: 
x² -5x + 6 = 
5 ± 25 - 4.1.6 / 2.1 ->obs.:25 - 4.1.6 dentro da raiz 
5 ± 1 / 2 -> obs.:1 dentro da raiz 
x' = 5+1 / 2 
x' = 3 

x" = 5-1 / 2 
x" = 2

Answer 2

$x^2-5x+6=0$

Coeficientes: a = 1, b = -5 e c = 6

$\Delta=b^2-4ac\\\Delta=(-5)^2-4\cdot1\cdot6\\\Delta=25-24\\\Delta=1$

$x=\frac{-b+-\sqrt{\Delta}}{2a}\\\\x=\frac{-(-5)+-\sqrt{1}}{2\cdot1}\\\\x=\frac{5+-1}{2}\\\\x_1=\frac{5+1}{2}=\frac{6}{2}=3\\\\x_2=\frac{5-1}{2}=\frac{4}{2}=2$


Espero ter ajudado.
Bons estudos! :)