Question

– x(ao quadrado) – 4x + 60 = 0

Answer 1

-x^2-4x+60=0(x-1)
x^2+4x-60=0

delta=b^2-4ac
delta=4^2-4(1x-60)
delta=16+240
delta=raiz de 256
delta=16

x=-bx+ou- delta/2a
x=-4+ou-16/2
x1=-4+16/2=12/2=6
x2=-4-16/2=-20/2=-10