Question

x ao quadrado+3x-6= -8 esse trabalho vale 10 e eu nao to entendendo a explicacao do professor preciso de ajud

Answer 1

$x^{2} +3x-6=-8 \\ x^{2} +3x-6+8=0 \\ x^{2} +3x+2 \\ delta = b^{2} -4*a*c \\ delta= 3^{2} -4*1*2 \\ delta=9-8 \\ delta=1 \\ \\ x= \frac{-b+- \sqrt{delta} }{2*a} \\ x= \frac{-3+- \sqrt{1}}{2*1} \\ x= \frac{-3+-1}{2} \\ \\ x_{1} = \frac{-3+1}{2} = \frac{-2}{2} = -1 \\ \\ x_{2} = \frac{-3-1}{2} = \frac{-4}{2} =-2 \\ \\ S{-1 , -2}$