Question

-x ao quadrado+3x+10

Answer 1

- x² + 3x + 10 = 0
Δ = 9 + 40
Δ = 49

x = -3 +- √49/-2
x = -3 +-7/-2
x' = - 3 +7/-2
x' = 4/-2 = -2
x'' = -3-7/-2
x'' = -10/-2 = 5        ok

Answer 2

-x"+3x+10=0(-1)
x"-3-10=0
/\ = (-3")-4.1. (-10)
/\ = 9+40
/\ = 49
x = -(-3)+/-7=
2.1
x' = +3+7=10 = 5
2 2
x" = +3-7 = 4 = 2
2 2

S = {5,2}



2 2