Question

x ao quadrado -19x+88=0

Answer 1

x²-19x+88=0
Δ= (-19)²-4.1.88
Δ=361-352
Δ=9
x=-(19)+-√9/2.1
x=19+-3$\frac{19+-3}{2}$
x'=$\frac{19+3}{2}$
x'=$\frac{22}{2}$
x'= 11
x"=$\frac{19-3}{2}$
x"=$\frac{16}{2}$
x"=8