Question

x ao quadrado - 10x - 56=0

Answer 1

$x^2-10x-56=0$

Resolvendo pela fórmula de Bhaskara, anexa

a=1  b=-10  c=-56

$delta=(-10)^2-4.1.(-56)=100+224=324 \\ \\ \sqrt{delta} = \sqrt{324} =18 \\ \\ x_{1} = \frac{-(-10)+18}{2.1} = \frac{28}{2} =14 \\ \\ x_{2} = \frac{-(-10)-18}{2} = \frac{-8}{2} =-4$

S={-4;14}

Answer 2

x² - 10x - 56 = 0   a) 1   b) - 10   c) - 56
Δ = b² - 4 . a . c
Δ = - 10² - 4 . 1 . -56
Δ = 100 + 224
Δ = 324

- b +/- √Δ / 2 . a
- ( - 10 ) +/- √324 / 2 . a
10 +/- 18 / 2
x' = 10 + 18 / 2 = 28/2 = 14
x'' = 10 - 18 / 2 = - 8/2 = - 4