Question

(X-7)(x-3)+10x=30 como resolver

Answer 1

(X-7)(x-3)+10x=30
x²-3x-7x+21+10x=30
x² +21 -30 = 0
x² -9 =0
(x+3)(x-3) =0

x+3 = 0
x= -3

x-3 = 0
x= 3

{3,-3)

Answer 2

(X-7)(x-3)+10x=3

$x^{2} - 3x - 7x + 21 + 10x = 30 \\ \\ x^{2} + 21 - 30 = 0 \\ \\ x^{2} = 0 \\ \\ (x - 3) \times (x - 3) = 0 \\ \\ x + 3 = 0 \\ \\ x = - 3 \\ \\ x - 3 = 0 \\ \\ x = 3 \\ \\ (3 \: \: - 3)$