Question

(X-5)^2=1 ME AJUDEM A RESOLVER

Answer 1

$(x-5)^2=1$

$x^2-10x+25=1$

$x^2-10x+24=0$

$\Delta=(-10)^2-4\cdot1\cdot24=100-96=4$

$x=\dfrac{-(-10)\pm\sqrt{4}}{2}=\dfrac{10\pm2}{2}=5\pm1$

$x'=5+1=6$

$x"=5-1=4$

$S=\{4,6\}$

Answer 2

( x - 5 )² = 1

( x - 5 ) . ( x - 5 ) = 1

x² - 5x - 5x + 25 - 1 = 0

x² - 10x + 24 = 0

a = 1
b = - 10
c = 24

x = -b± raíz de b² - 4 . a . c / 2 . a

x = -(-10) ± raíz de (-10)² - 4.1.24 / 2 . 1

x = 10 ± raíz de 100 - 96 / 2

x = 10 ± raíz de 4 / 2

x = 10 ± 2 / 2

x¹ = 10 + 2 / 2 = 12/2 = 6

x² = 10 - 2 / 2 = 8/2 = 4


Solução { 6 , 4 }