Question

(x+4).(x-3)-(1-x).(x-2)=14

Answer 1

[ ( x + 4)( x - 3)] - [ (1 - x) ( x -2)] = 14
[ x² - 3x + 4x - 12 ] - [ x - 2  -x² + 2x ] = 14
x² + x² -3x + 4x - 2x - x -12 + 2 ] = 14
[ 2x² -2x - 10 ] =14
[ 2x² - 2x - 10 - 14] = 0
2x² - 2x - 24 = 0
x² - x - 12 = 0
delta = 1 +48 = 49 ou +-V49 = +-7 ****

x = ( 1 +-7)/2
x1 = 8/2 = 4 ****
x2 = -6/2 = -3 ****