(x-4)2 - (x-1)2= 10 -x2 me ajudem precisoooo !
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(x-4)^2-(x-1)^2=10-x^2
(x^2-2.x.4+4^2)-(x^2-2.x.1+1^2)=10-x^2
(x^2-8x+16)-(x^2-2x+1)=10-x^2
x^2-8x+16-x^2+2x-1=10-x^2
-6x+15=10-x^2
x^2-6x+15-10=0
x^2-6x+5=0
∆=b^2-4.a.c
∆=(-6)^2-4.1.5
∆=36-20
∆=16
x=-b+-√∆/2a
x=6+-√16/2.1
x=6+-4/2
x'=6+4/2
x'=10/2
x'=5
x"=6-4/2
x"=2/2
x"=1
(x^2-2.x.4+4^2)-(x^2-2.x.1+1^2)=10-x^2
(x^2-8x+16)-(x^2-2x+1)=10-x^2
x^2-8x+16-x^2+2x-1=10-x^2
-6x+15=10-x^2
x^2-6x+15-10=0
x^2-6x+5=0
∆=b^2-4.a.c
∆=(-6)^2-4.1.5
∆=36-20
∆=16
x=-b+-√∆/2a
x=6+-√16/2.1
x=6+-4/2
x'=6+4/2
x'=10/2
x'=5
x"=6-4/2
x"=2/2
x"=1
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