Question

x+3y+z=0
3x-3y+z=8
2y+z=0

Answer 1

x+3y+z=0

3x-3y+z=8

2y+z=0

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2y+z=0

2y= -z

y= -z/2

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x+3y+z=0

x+3(-z/2)+z=0

x-3z/2+z=0

x-3z+z=0*2

x-3z+z=0

x-2z=0

x= 2z

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X+3y+z=0

2z+3(-z/2)+z=0

2z-3z/2+z= 0

2z-3z+z= 0*2

2z-3z+z= 0

6z=0

z=0/6

z=0

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y= -z/2

y= -0/2

y=0

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x= 2z

x= 2*0

x= 0

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R= O valor de x,y e z é 0.

Espero ter ajudado!