Question

x^3+y^3-3xy derivação implícita?​

Answer 1

x³+y³-3xy=0

3x²+3y²y'-(3xy'+3y)=0

3y²y'-3xy'=3y-3x² *

y'(3y²-3x)=3y-3x²

y'=(3y-3x²)/(3y²-3x)

y'=3(y-x²)/3(y²-x)

y'=(y-x²)/(y²-x)