Question

(x+3) (x-6)=-18 como resolve?

Answer 1

x² - 6x + 3x - 18 = -18
x² - 3x -18 +18= 0
x² -3x = 0

a=1 b=3 c=0

delta= b²-4ac
delta= (3)² - 4 (1) . (0)
delta = 9 - 0
delta = 0

x= -b +/- raiz de Δ / 2a
x= -3 +/- $\sqrt{9}$/2.1
x= -3 +/- 3 / 2

x¹ = -6/2  = -3
x² = 0