Question

(x-3) (x+2)
me respondem por favor ​

Answer 1

Resposta:

x² + 2x -3x -6

x² -x -6 = 0

bhaskara:

Δ = b²- 4.a.c

Δ = -1² -4.1.(-6)

Δ = 1 + 24

Δ = 25

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$x = \frac{-b+-\sqrt{25} }{2\\}$

$x = \frac{-1 +- 5}{2}$

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x' = $\frac{-1+5}{2} =\frac{4}{2} = 2$

x'' = $\frac{-1-5}{2}=\frac{-6}{2}=-3$