Question

(x+3) elevado a 2 + (x+3) elevado a dois-116=0

Answer 1

Resposta:

$\left(x+3\right)^2=58$

$\left(x+3\right)^2+\left(x+3\right)^2-116=0$

$\left(x+3\right)^2+\left(x+3\right)^2-116+116=0+116$

$\left(x+3\right)^2+\left(x+3\right)^2=116$

$2\left(x+3\right)^2=116$

$\frac{2\left(x+3\right)^2}{2}=\frac{116}{2}$

$\left(x+3\right)^2=58$

$x=\sqrt{58}-3,\:x=-\sqrt{58}-3$