Question

㏒(x-3) base 2 + ㏒x base 2=2

Answer 1

Resposta

$log_{2} (x - 3) + log_{2} x = 2\\\frac{log_{2} x}{log_{2} 3} + x= 2^2\\\frac{x}{3}+ x= 4\\\ 2x= 12\\x= 12/2\\x= 6$