Question

(x-3) ao quadrado - (x-2)*(x+2)-(x+1)

Answer 1

$(x-3)^2-(x-2)(x+2)-(x+1)=x^2-6x+9-(x^2-4)-x-1=$

$x^2-6x+9-(x^2-4)-x-1=x^2-6x+9-x^2+4-x-1=$

$x^2-6x+9-x^2+4-x-1=-7x+9$