Question

(x^3-4)^2-16 / x^2+2x+4

Answer 1

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$\frac{(x^3-4)^2-16}{x^2+2x+4} = \\ \\ \frac{x^6-8x^3+16-16}{(x^2+2x+4)} = \\ \\ \frac{x^6-8x^3}{x^2+2x+4} = \\ \\ \frac{x^3(x^3-8)}{x^2+2x+4} = \\ \\ \frac{x^3(x-2)(x^2+2x+4)}{x2+2x+4} = \\ \\ x^3(x-2)=x^4-2x^3$