Question

( x+3, 2x-2, 4x-13) Seja uma P.A.​

Answer 1

x+3, 2x-2, 4x-13

definindo a razão

r=a2-a1=a3-a2

r=a1+a3=2a2

a2=a1+a3/2

2x-2=x+3+4x-13/2

4x-4=5x-10

[x=6]

*****

$\boxed{ \boxed{ \boxed{ \mathsf{x = 6}}}}$

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Answer 2

r = r

a2 -a1 = a3 -a2

2(a2) = a3 +a1

4x -4 = 5x -10

6 = x

{9 , 10 , 11 , ...}

r = 1