Question

(x - 3)2 =

(5y – 1)2 =

(3x-2y)2 =

(x-4y)2 =

(4a-3b)2 =

(7a-b)2 =

(5x-5y)2 =

(x-2y)2 =

(12x-y)2 =

(10a-3b)2 =

Answer 1

Resposta:

as resposta estão na resolução abaixo de cada item.

Explicação passo-a-passo:

(x - 3)2 = >  $(x-3) . (x - 3) =>x^{2} -3x -3x +3^{2} => x^{2} - 6x + 9$

(5y – 1)2 =  $(5y)^{2} -1^{2} => (5y -1). (5y -1)=> 25y^{2} - 5y - 5y + 1 = 25y^{2} - 10y + 1$

(3x-2y)2  => (3x -2) . (3x -2) => $9x^{2} -12xy - 12xy + 4y^{2} => 9x^{2} -24xy + 4y^{2}$

(x-4y)2 = >$(x - 4y). (x -4y) = x^{2}-4xy -4xy + 16y^{2} => x^{2} -8xy + 16y^{2}$

(4a-3b)2 = $(4a - 3b). (3a -4b) = 16a^{2}-12ab -12ab + 9b^{2} => 16a^{2}-24ab + 9b^{2}$

(7a-b)2 = $(7a - b). (7a -b) = 49a^{2}-7ab -7ab + b^{2} => 49a^{2}-14ab + b^{2}$

(5x-5y)2 = $(5x - 5y). (5x -5y) = 25x^{2}-25xy -25xy + 25y^{2} => 25x^{2}-50xy+ 25y^{2}$

(x-2y)2 = $(x - 2y). (x -2y) = x^{2}-2xy -2xy + 4y^{2} => x^{2}-4xy + 4y^{2}$

(12x-y)2 = $(12x - y). (12x -y) = 144x^{2}-12xy -12xy + y^{2} => 44x^{2}-24xy + y^{2}$

(10a-3b)2 =$(10a - 3b). (10a -3b) = 100a^{2}-30ab -30ab + 9b^{2} => 100a^{2}-60ab + 9b^{2}$