Question

x+2y-2=2 2x-y+2=3 x+y+z=6

Answer 1

$(x + 2y =4 \\ (2x - y = 1 \\ (x + y + z = 6 \\ \\ \\ (x = 4 - 2y \\ (2y - y = 1 \\ (x + y + z = 6 \\ \\ \\ 2( 4 - 2y) - y = 1 \\ 4 - 2y + y + z = 6 \\ \\ \\ y = \frac{7}{5} \\ - y + z = 2 \\ \\ \\ - \frac{7}{5} + z = 2 \\ \\ \\ z = \frac{17}{5} \\ \\ \\ x = 4 - 2 \times \frac{7}{5} \\ \\ \\ x = \frac{6}{5} \\ \\ \\ (x \: \: y \: \: z \: \: ) = ( \frac{6}{5} \frac{7}{5} \frac{17}{5} )$