Matemática, perguntado por emandreusbbianchi, 5 meses atrás

x/2 + y = 5
x - 3y = 5
alguém me ajuda por favor

Soluções para a tarefa

Respondido por Lyonzinw
11

(x, y) = (8, 1)

\Large{\sf{\Huge   ▱▰▱▰▱▰▱▰▱▰▱▰▱}}

\sf \Large\begin{cases} \sf \red{\frac{x}{2}    }+  \green{y    } = \blue{    5} \\ \sf \pink{  x  }  \purple{  - }  \orange{  3y } \red{=    }  \green{5    } \end{cases}

 \:

\sf \red{ \frac{x}{2}   }  \green{+    }  \blue{ y   }  \pink{ =   }  \purple{   5} \\ \sf \orange{   y} \red{ =   }  \green{  5  }  \blue{   - }  \pink{ \frac{x}{2}   }

 \:

\sf \red{    x}  \green{ -   }  \blue{  3  }  \pink{ (5   }  \purple{-   }  \orange{  \frac{x}{2}) } \red{=    }  \green{ 5   }  \\ \sf \blue{   x }  \pink{   - }  \purple{15   }  \orange{   +} \red{   \frac{3x}{2} }  \green{  =  }  \blue{   5}\\ \sf  \pink{\frac{5}{2}    }  \purple{x   }  \orange{-   } \red{ 15   }  \green{=    }  \blue{    5} \\ \sf \pink{  5x  }  \purple{-   }  \orange{ 30  } \red{   = }  \green{    10} \\ \sf \blue{   5x }  \pink{    =}  \purple{  10 }  \orange{+   } \red{   30 }\\ \sf  \green{ 5x   }  \blue{ =   }  \pink{   40 } \\ \sf \purple{ x  }  = \orange{ \frac{40}{5}  }\\ \sf\Huge\boxed{\large\boxed{ \sf\blue{x} = \red{8}}}

 \:

\sf \red{    \frac{(8)}{2} }  \green{  +  }  \blue{y    }  \pink{=    }  \purple{  5 } \\ \sf \orange{4   } \red{+  }  \green{ y   }  \blue{ =   }  \pink{  5  } \\ \sf \purple{   y}  \orange{  = } \red{  5  }  \green{ -   }  \blue{   4 } \\ \sf \Huge\boxed{\large \boxed{\sf\pink{  y }  \purple{ =  }  \orange{  1 }}}

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