Question

(x+2)×(x-6)=0 ??????????????

Answer 1

(x + 2)(x - 6) = 0
x² - 6x + 2x - 12 = 0
x² - 4x - 12 = 0

Coeficientes: a = 1, b = -4 e c = -12

Δ = b² - 4ac
Δ = (-4)² - 4.1.(-12)
Δ = 16 + 48
Δ = 64

$x=\frac{-b+/-\sqrt{\Delta}}{2a}\\x=\frac{-(-4)+/-\sqrt{64}}{2.1}\\x=\frac{4+/-8}{2}\\x_1=\frac{4+8}{2}\\x_1=\frac{12}{2}\\x_1=6\\x_2=\frac{4-8}{2}\\x_2=\frac{-4}{2}\\x_2=-2$


Espero ter ajudado.
Bons estudos!  :)